Answer:
The speed of the arrow was 112.76 m/s
Explanation:
Angle the arrow made with the ground, ∅ = 3⁰
v = u tan∅...............(1)
v = gt........................(2)
Equating (1) and (2)
gt = u tan ∅
t = (u tan ∅)/g..............................(3)
g = 9.8 m/s²
Speed = (distance ,s, covered by the arrow)/time taken
u = s/t
t = s/u ................................(4)
Equating (3) and (4)
s/u = (u tan ∅)/g
Distance, s = 68m
68/u = (u tan 3°)/9.8
9.8 * 68 = u² tan 3°
u² = (9.8 * 68)/tan 3°
u² = 666.4/0.0524
u² = 12715.67
u = √12715,67
u = 112.76 m/s
