Answer:
B. A repulsive force of 8.0*10^3 N.
Explanation:
As we know by Coulomb's law that the electrostatic force between two charges is given as
[tex]F = \frac{kq_1q_2}{r^2}[/tex]
here we know that
[tex]q_1 = -2 \times 10^2 C[/tex]
[tex]q_2 = -4 \times 10^{-8} C[/tex]
r = 3.0 m
now we have
[tex]F = \frac{(9 \times 10^9)(2 \times 10^2)(4\times 10^{-8})}{3^2}[/tex]
[tex]F = 8000 N[/tex]
since both charges are similar charges so they will repel each other by the force we calculated above so correct answer will be
B. A repulsive force of 8.0*10^3 N.
