Answer:
60feets
Step-by-step explanation:
The question is incomplete. The complete question is "Let y = safe load in pounds and x = length in feet of a horizontal beam. A constant of proportionality k exists such that y = k/x. If a beam can hold 2,000 pounds at 15 feet, what maximum length should be used to safely support 500 pounds"
Since y = k/x
k = xy
If a beam can hold 2,000 pounds at 15 feet, x = 15ft y = 2000pounds
K = 15×2000
k = 30,000
To get the maximum length that should be used to safely support 500 pounds, we will use the relationship k = xy where y = 500pounds, k = 30000
x = k/y
x = 30000/500
x = 60feets
The maximum length that should be used to safely support 500 pounds is 60feets
