Rasheed bought two kinds of candy bars, chocolate and toffee, that came in packages of 2 bars each. He handed out \frac{2}{3} of the chocolate bars and \frac{3}{5} of the toffee bars. How many packages of chocolate bars did Rasheed buy?

Respuesta :

Answer:

Rasheed bought 9 packages of chocolate bars

Step-by-step explanation:

Rasheed bought two kinds of candy bars, chocolate and toffee, that came in packages of 2 bars each.

Let 'cb' represent the number of chocolate bars that Rasheed bought

Let 'tb' represent the number of toffee bars that Rasheed bought

If Rasheed bought 1 fewer package of chocolate bars than toffee bars; we have the following suitable expression

cb = tb - 1

Also; he handed out [tex]\frac{2}{3}[/tex] of the cb and [tex]\frac{3}{5}[/tex] of tb; we have:

[tex]\frac{2}{3} *cb = \frac{3}{5}*tb[/tex]

[tex]10cb = 9tb[/tex]

If we make tb the subject of the formula since we are only looking for the number of chocolate bars Rasheed bought; we have:

[tex]tb=\frac{10}{9} cb[/tex]

From the previous expression cb = tb - 1

1 = tb - cb

Replacing [tex]tb=\frac{10}{9} cb[/tex] in the above equation; we have:

[tex]1= \frac{10cb}{9} -\frac{cb }{1}[/tex]

[tex]1 = \frac{1cb-9cb}{9}[/tex]

[tex]1 = \frac{1cb}{9}[/tex]

[tex]cb = 1*9[/tex]

cb = 9

Hence,Rasheed bought 9 packages of chocolate bars

Answer:

Rasheed bought 9 packages of chocolate bars

Step by step explanation:

Let x represent the number of packages of chocolate bars

and y represent the number of packages of toffee bars.

Rasheed handed out 2/3 × 2x of the chocolate bars

and

3/5 × 2y of the toffee bars.

Rasheed bought 1 fewer package of chocolate bars than toffee bars

=> x = y - 1 ...........................(1)

Rasheed handed out the same number of each kind of candy bar

=>2/3 × 2x = 3/5 × 2y

4x/3 = 6y/5

x = (3/4)(6y/5) = 9y/10...................(2)

Using the value of x in (2) in (1)

9y/10 = y - 1

(1 - 9/10)y = 1

(1/10)y = 1

y = 10

Therefore, y is 10 and x is 9