How do I find area of this polygon?
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Answer:
Area = 297cm²
Step-by-step explanation:
Let Polygon be ABCDE
Draw a line CE parallel to AB which make right angles at F.
now, CE = AB
also, CF = FE = 22 / 2 = 11cm
and the line drawn from the vertex of the D = 19cm to G on AB.
AE = BC = FG = 8cm
so, FD = 19 - 8 = 11cm
Now the Area.
Area of the polygon = Area of the Rectangle ABCE + 2 x Area of either Triangle
(we need not calculate both the area of triangle as two sides of the triangle is equal)
Area of the Rectangle ABCE = l x b
here l = 22 cm and b = 8cm
= 22 x 8 = 176cm² ---------------(i)
2 x Area of either Triangle = 2 x 1/2 x b x h
here, b(CF or EF) = 11cm and h(FD) = 11cm
= 11 x 11 = 121cm² ----------------(ii)
Area of the polygon = Area of the Rectangle ABCE + 2 x Area of either Triangle
From (i) and (ii),
Area = 176 + 121
Area = 297cm²