Answer:
236.5 N
Explanation:
The tension in the rope will be given by
[tex]T=m(g+\frac {v^{2}}{r})[/tex] where T is the tension on the rope, m is the mass of the ball, v is the speed of the ball of the ball at the lowest point and r is the length of the ball.
Since F=mg then making m the subject, [tex]m=\frac {F}{g}[/tex] where F is the force and g is acceleration due to gravity. Now replacing m with the above in the dirst equation then
[tex]T=\frac {F}{g}\times (g+\frac {v^{2}}{r})[/tex]
Substituting 150 N for F, 9.81 for g, 5.1 m/s for v and 4.6 m for L then
[tex]T=\frac {150}{9.81}\times (9.81+\frac {5.1^{2}}{4.6})=236.45791783006 N\approx 236.5 N[/tex]
The tension in the rope at that point is 236.51 N.
Since
The weight of the ball W = 150 N
The length of the rope l=4.6m
And, the velocity of the ball at the lowest point v=5.1m/s
Now the mass of the ball is
= 150 / 9.8
= 15.30 kg
Now the tension should be
= 150 + (15.30*5.1^2)/ 4.6
= 236.51 N
Learn more about rope here: brainly.com/question/18997330
