Answer:
its molecular formula must be C10H16O with 2 rings.
Explanation:
the number of rings of the camphor has to be calculated, we have M + = 152.12 in the mass spectrum and it has three double bonds and one ring. The base beak has great abundance.
Since camphor is a single ketone, and M+/MC = 12 ~~ 8, its molecular formula must be C10H16O, accordingly, the number of rings = (10 * 2-16)/2 = 2.