contestada

17) List the ways five dogs a Beagle, a Collie, a Greyhound, a Poodle and a
Scottie can be put in pairs without counting alternate orders. How many pairs
are there? Is this a combination or permutation?

Respuesta :

Edufirst

Answer:

  • 10 pairs
  • It is a combination

Explanation:

This is a combination because the order does not matter: the Beagle - Collie couple is the same as the Collie - Beagle couple, so it is only counted once.

The formula for combinations is:

           [tex]C(m,n)=\dfrac{m!}{n!\cdot (m-n)!}[/tex]

For five diffferent dogs to be put in pairs, the number of different pairs is:

         [tex]C(5,2)=\dfrac{5!}{2!\cdot (5-2)!}=\dfrac{5\times 4}{2}=10[/tex]