Good morning ☕️
Answer:
[tex](\frac{-2}{3} , -2)[/tex]
Step-by-step explanation:
3x+y=-4 (1)
3x-4y=6 (2)
solving by elimination:
(1) - (2) ⇒
3x + y = -4
3x - 4y = 6
________
0 + 5y = -10
5y = -10 ⇔ y = -2
(2) ⇒ 3x-4y=6 ⇒ 3x-4(-2)=6 ⇒ 3x = 6 - 8 = -2 ⇒ x = -2/3
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:)
Answer: x = 2, y = -2
Step-by-step explanation:
Subtract the two equations:
3x+y=-4......equation 1
3x-4y=6.......equation 2
5y = -10
Divide both sides by 5 to get the value of y
y = -2
Insert the value of y into equation 1 to get the value of x
3x + y = -4
3x + (-2) = -4
3x -2 = 4
3x = 4 +2
3x = 6
Divide both sides by 3 to get the value of x
x = 6/3
x = 2
Check: insert the values of x and y into equation 1
3x + y = 4
3 (2) + (-2) = 4
6 - 2= 4
I hope this is clear, please mark as brainliest answer.
