580 nm light shines on a double slit
with d = 0.000125 m. What is the
angle of the first dark interference
minimum (m = 1)?
(Remember, nano means 10-9.).
(Unit = deg)ā€‹

Respuesta :

Answer:

Angular position of the first minimum is 0.27 degree

Explanation:

As we know by the formula of single slit diffraction pattern

[tex]a sin\theta = m\lambda[/tex]

here we have

a = d = 0.000125 m

for m = 1

[tex]\lambda = 580 nm[/tex]

now we have

[tex]0.000125 sin\theta = 580 \times 10^{-9} [/tex]

[tex]sin\theta = 4.64 \times 10^{-3}[/tex]

[tex]\theta = 0.27 degree[/tex]

Answer:

.133

Explanation:

x=sin^(-1)(((1-(1)/(2))(580*10^(-9)))/(.000125)) took me a while to figure it out but I just took the quiz and I promise this answer is correct please mark brainliest