Answer:
Empirical formula is K₂O
Explanation:
These are the elements and their mass, from the compound
34.3 g of K
7.02 g of O
We determine the moles:
34.3 g / 39.1 g/mol = 0.877
7.02 g / 16g/mol = 0.434
We divide the moles, by the lowest value:
0.877 / 0.434 = 2 mol of K
0.434 / 0.434 = 1 mol of O
Empirical formula is K₂O
Answer:
The empirical formula is K2O
Explanation:
Step 1: Data given
Mass of potassium (K) = 34.3 grams
Mass of oxygen (O) = 7.02 grams
Molar mass of K = 39.1 g/mol
Molar mass of O = 16.0 g/mol
Step 2: Calculate moles
Moles = mass / molar mass
Moles K = 34.3 grams / 39.1 g/mol
Moles K = 0.877 moles
Moles O = 7.02 grams / 16.0 g/mol
Moles O = 0.439 moles
Step 3: Calculate the empirical formula
We divide by the smallest amount of moles
K: 0.877 moles / 0.439 moles = 2
O: 0.439 moles / 0.439 moles = 1
This means for each mol oxygen we have 2 moles of potassium
The empirical formula is K2O
