Answer:
Explanation:
1)
As we will consider the puck only as our system then during the collision with the box the normal force during the time of collision will behave like external force on the puck
So as per Newton's II law we know that
[tex]F = \frac{dP}{dt}[/tex]
so momentum of the puck is not conserved
Also we know that puck and the box both stick together so this is inelastic collision
So here we can say that energy of puck is lost during the collision
so correct answer will be
a. puck loses some but not all of its original momentum.
2)
When we will consider the box + puck as our system then the force between puck and the box is internal force of the system
and since there is no external force on it
So the momentum of the system is conserved
But here we know that the collision between them is inelastic collision so here mechanical energy is not conserved
so correct answer here will be
f. conserves momentum but loses some mechanical energy