[tex]\frac{V_{1} }{n_{1} } =\frac{V_{2} }{n_{2} }[/tex] where V₁ is a volume, n₁ is a number in moles, V₂ is a second volume, and n₂ is its corresponding number in moles.
In our data:
Let's plug our values in the equation above.
[tex]\frac{39.2}{3.86} =\frac{17.3}{n} \\\\10.2=\frac{17.3}{n} \\\\10.2n=17.3\\\\n=1.70[/tex]
Note: You could rearrange the equation before plugging in values for less algebraic manipulation.
We're not done yet. Now, you have to subtract this number of moles from the initial value to find the difference, since the question states "how many moles...have been lost".
[tex]3.86-1.70=2.16[/tex]
2.16 moles would have been lost
Answer:
2.16 moles are lost from the container
Explanation:
Step 1: Data given
Moles of acetylene = 3.86 moles
Volume = 39.2 L
The volume reduces to 17.3 L
Temperature and pressure is constant
Step 2: Calculate the new number of moles acetylene
V1/ n1 = V2/ n2
⇒with V1 = the initial volume in the container = 39.2 L
⇒with n1 = the initial number of moles acetylene = 3.86 moles
⇒with V2 = the new volume in the container after the leak = 17.3 L
⇒with n2 : the new number of moles = TO BE DETERMINED
39.2 L / 3.86 moles = 17.3 L / n2
n2 = 1.70 moles
Step 3: Calculate the loss of moles
Loss of moles = 3.86 - 1.70 = 2.16 moles
2.16 moles are lost from the container
