Respuesta :
Answer:
Tyler purchased 10 cans of soup and 5 frozen dinners.
Step-by-step explanation:
1. Let's review the information given to us to answer the question correctly:
Amount of sodium per can of soup = 300 mg
Amount of sodium per frozen dinner = 550 mg
They all collectively contain 5,750 mg of sodium
Tyler purchased twice as many cans of soup as frozen dinners
2. Determine the number of cans of soup purchased and the number of frozen dinners purchased.
Let s to represent the number of cans of soup Tyler purchased
Let d to represent the number of frozen dinners Tyler purchased
Let's write our equation of systems:
s = 2d (1st equation)
300s + 550d = 5,750 (2nd equation)
************************************************
Substituting s and solving for d in the 2nd equation:
300s + 550d = 5,750
300 * 2d + 550d = 5,750
600d + 550d = 5,750
1,150d = 5,750
d = 5,750/1,150
d = 5 ⇒ s = 2 * 5 = 10
Tyler purchased 10 cans of soup and 5 frozen dinners.
Let's prove d = 5 and s = 10 are correct:
300 * 10 + 550 * 5 = 5,750
3,000 + 2,750 = 5,750
5,750 = 5,750
We proved d = 5 and s = 10 are correct
The number of cans of soup purchased is 10 and number of frozen dinner purchased is 5.
Given that,
- Each can of soup has 300 mg of sodium and each frozen dinner has 550 mg of sodium.
- Tyler purchased twice as many cans of soup as frozen dinners and they all collectively contain 5750 mg of sodium.
- Here we assume no of soup be s and no of frozen dinner be d.
Based on the above information, the calculation is as follows
s = 2d
And,
300s + 550d = 5,750
Now put the value of s in the above equation
300(2d) + 550d = 5,750
600d + 550d = 5,750
1,150d = 5,750
d = 5
So, s = 2(5)
= 10
Learn more: brainly.com/question/17429689