Answer:
Option B) 0.2143
Step-by-step explanation:
We are given the following in the question:
Numbers of exposures(x): 4,3,7
We have to find the maximum likelihood estimate of p.
Formula:
[tex]\hat{p} = \dfrac{n}{\sum x_i}[/tex]
Putting the values, we get,
[tex]\hat{p} = \dfrac{3}{3+4+7} = \dfrac{3}{14} = 0.2143[/tex]
Thus, the correct answer is
Option B) 0.2143