Answer:
a)p = 0.67 U/V
b)M´/M = 3
c)v´rms/vrms = 0.58
d)C´v/Cv = 1
Explanation:
a) An equation must be found that relates the pressure to the volume of the gas. Then we will use these equations for U and write p in relation to U/V. According to the ideal gas law, we have:
pV = NkbT
clearing p:
p = (Nkb)*T/V = 0.67 U/V
b) the ratio of the new molar mass M´ to the old molar mass M would be equal to:
M´/M = 3
c) According to the equation vrms = (<v^2>)^1/2. Monatomic particle has three degrees of freedom. The kinetic energy associated with each degree of freedom is equal to K = (1/2)*kB*T. Another equation for kinetic energy is equal to K=(1/2)*m*<vx^2>
v´rms/vrms = 0.58
d) The total heat capacity of a gas can be calculated by multiplying the heat capacity per mole by the number of moles of the gas particles n=N/NA
C´v/Cv = 1