Answer:
E = 5.04 10³ N / C
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Explanation:
For the sphere to be in equilibrium the electric force must be equal to the weight of the sphere, we write the equilibrium equation
[tex]F_{e}[/tex] - W = 0
q E = mg
E = mg / q
To find the mass of the Teflon sphere we use the density
ρ = m / V
m = ρ V
m = ρ 4/3 π r³
Teflon density is rho = 2.2 g / cm³ (1 kg / 10³ g) = 2.2 10⁻³ kg / cm³
The radius of the sphere
d = 10 mm = 1 cm
r = 0.5 cm
m = 2.2 10-3 4/3 π 0.5³
m = 3.6 10⁻⁴ kg
Let's calculate
E = 3.6 10⁻⁴ 9.8 / 700 10-9
E = 5.04 10³ N / C
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