Answer:
a) final displacement of the cyclist = 20.8km
b) average velocity = 18 .35km/hr
Explanation:
Given that,
cyclist rides 8.0 km east for 20 minutes
heads west for 8 minutes and 3.2 km
rides east for 16 km, which takes 40 minutes
The cyclist has 3 vector
v₁ = 8i km
v₂ = -3.2i km
v₃ = 16i km
The final isplacement is the sum of vector
= 8 + (-3-2) + 16
= 20.8km
final displacement of the cyclist = 20.8km
b) average velocity we have
[tex]v_{avg}=\frac{Total\cdot Displacement}{Total\cdot Time}\\\\=\frac{20.8}{20+8+40}\\=0.305km/min\\=18.35km/hr\\[/tex]
average velocity = 18 .35km/hr
