Answer: y=2
Step-by-step explanation:
4y^2-16y+16=0 To "solve" means to find the value of x for which this equation is true.
y^2 -4y + 4 = 0 [divide by 4; this is the same equation]
(y-2)(y-2) = 0 [You may factor or use the quadratic equation]
y=2 and y=2 [the same answer]
Check:
Does (2)2 - 4(2) + 4 = 0 ?
4 - 8 + 4 = 0 ?
0 = 0 ? yes
