Answer:
magnitude of the magnetic field must be 1.56 T
Explanation:
As we know that the magnetic force on moving charge is given as
[tex]F = q(\vec v \times \vec B)[/tex]
now when charge is moving along z direction then magnetic force is ZERO
so here we can say that magnetic field must be parallel to velocity of the charge i.e. along z direction
now when charge is moving along x direction then we have
[tex]F = qvB[/tex]
[tex]2.1 \times 10^{-13} = (1.6 \times 10^{-19})(8.4 \times 10^5) B[/tex]
so we have
[tex]B = 1.56 T[/tex]
magnitude of the magnetic field must be 1.56 T
