The average price of homes sold in the U.S. in the past year was $220,000. A random sample of 81 homes sold this year showed an average price of $210,000. It is known that the standard deviation of the population is $36,000. At level of significance (a) 0.05, conduct the hypothesis test to determine if there has been a significant decrease in the average price homes.

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Answer:

There is a significant decrease in the average price homes.

Step-by-step explanation:

Let X represent the prices of homes sold in the U.S. in the past year

given that

[tex]\mu = 220000\\n =81\\\sigma = 36000\\\bar x =210000\\\alpha = 0.05[/tex]

Create hypotheses as

[tex]H_0: \bar x = 220000\\H_a: \bar x <220000[/tex]

(Left tailed test at 5% significance)

Mean difference = -10000

Std error of mean = [tex]\frac{\sigma}{\sqrt{n} } \\=4000[/tex]

Since population std deviation is known, we can do z test

Z = mean diff/std error = -2.50

p value = 0.00621

Since p <0.05 we reject null hypothesis.

There is a significant decrease in the average price homes.

Here, P < 0.05 then reject the null hypothesis and accept the alternate hypothesis.

There has been a significant decrease in the average price homes.

Given that,

The average price of homes sold in the U.S. in the past year was $220,000.

A random sample of 81 homes sold this year showed an average price of $210,000.

The standard deviation of the population is $36,000.

We have to determine,

At level of significance (a) 0.05, conduct the hypothesis test to determine if there has been a significant decrease in the average price homes.

According to the question,

The hypothesis test to determine if there has been a significant decrease in the average price homes.

Let, x represent the prices of homes sold in the U.S. in the past year.

The hypothesis test is determined by formula,

[tex]Z_s_t_a_t = \dfrac{x_1-\mu}{\frac{\sigma} {\sqrt{n}}}[/tex]

Where, Population mean, μ = $220,000 ,

Sample mean,[tex]x_1[/tex]  = $210,000 , Sample size, n = 81 ,  

Significance level, α = 0.051 ,

Population standard deviation, σ = $36,000.

The null and the alternate hypothesis,

[tex]H_0 ;\mu = 220000 dollars\\\\H_a; \mu<210000[/tex]

Substitute all the values in the formula,

[tex]Z_s_t_a_t = \dfrac{210000-220000}{\frac{36000} {\sqrt{81}}}\\\\Z_s_t_a_t = \dfrac{-100000}{\frac{\36000} {9}}\\\\Z_s_t_a_t = \dfrac{-10000}{4000}\\\\Z_s_t_a_t = -2.5[/tex]

The p-value from the z-table,  

P-value = 0.00621

Here,  P-value < Significance level

Since, P < 0.05 then reject the null hypothesis and accept the alternate hypothesis.

Hence, There has been a significant decrease in the average price homes.

To know more about Hypothesis click the link given below.

https://brainly.com/question/14965054