Respuesta :
Answer: The mass of sand in the sample is 36.24 grams.
Explanation:
The equation used to calculate heat released or absorbed follows:
[tex]q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})[/tex]
where,
q = heat absorbed = 1364 J
m = mass of sand = ?
c = heat capacity of sand = 0.84 J/g°C
[tex]T_{initial}[/tex] = initial temperature = 22.2°C
[tex]T_{final}[/tex] = final temperature = 67°C
Putting values in above equation, we get:
[tex]1364=m\times 0.84\times (67-22.2)\\\\m=36.24g[/tex]
Hence, the mass of sand in the sample is 36.24 grams.
Taking into account the definition of calorimetry, the mass of sand in the sample is 36.24 grams.
In first place, calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
In this way, between heat and temperature there is a direct proportional relationship (Two magnitudes are directly proportional when there is a constant so that when one of the magnitudes increases, the other also decreases; and the same happens when either of the two decreases .).
The constant of proportionality depends on the substance that constitutes the body and its mass, and is the product of the specific heat by the mass of the body.
So, the equation that allows to calculate heat exchanges is:
Q = c× m× ΔT
where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.
In this case, you know:
- Q= 1364 J
- c= 0.84 [tex]\frac{J}{gC}[/tex]
- m= ?
- ΔT= Tfinal - Tinitial= 67 C - 22.2 C= 44.8 C
Replacing in the expression to calculate heat exchanges:
1364 J= 0.84[tex]\frac{J}{gC}[/tex]× m× 44.8 C
Solving:
[tex]m=\frac{1364 J}{0.84 \frac{J}{gC}x44.8C }[/tex]
m=36.24 grams
In summary, the mass of sand in the sample is 36.24 grams.
Learn more:
- brainly.com/question/11586486?referrer=searchResults
- brainly.com/question/24724338?referrer=searchResults
