Answer:
Step-by-step explanation:
If you're looking for the times, t, when the height, h, is 68, then sub in 68 for h and factor the resulting quadratic.
[tex]68=-16t^2+140t[/tex] and, getting everything on one side and setting the quadratic equal to 0:
[tex]-16t^2+140t-68=0[/tex]
Plug this into the quadratic formula and solve for t.
t = .516 sec and
t = 8.234 sec