Answer:
[tex]1/3[/tex]
Step-by-step explanation:
The rounds that give two heads can be neglected.
Looking at the first round that gives at least one tail let T
denotes the number of tails is that round
[tex]P(T=2\mid T\geq1)=\frac{P(T=2)}{P(T\geq1)}=\frac{1/4}{3/4}=\frac13[/tex]