From 19 measurements of a pressure controller, the mean operating pressure is 4.97 kPa with a standard deviation of 0.0461 kPa. Find: If more measurements are taken, estimate the expected range of pressure for 95% of the measurements.

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Answer:

[tex]4.97-2.10\frac{0.0461}{\sqrt{19}}=4.95[/tex]    

[tex]4.97+2.10\frac{0.0461}{\sqrt{19}}=4.99[/tex]    

So on this case the 95% confidence interval would be given by (4.95;4.99)  

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

[tex]\bar X =4.97[/tex] represent the sample mean

[tex]\mu[/tex] population mean (variable of interest)

s=0.0461 represent the sample standard deviation

n=19 represent the sample size  

Confidence interval

The confidence interval for the mean is given by the following formula:

[tex]\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}[/tex]   (1)

In order to calculate the critical value [tex]t_{\alpha/2}[/tex] we need to find first the degrees of freedom, given by:

[tex]df=n-1=19-1=18[/tex]

Since the Confidence is 0.95 or 95%, the value of [tex]\alpha=0.05[/tex] and [tex]\alpha/2 =0.025[/tex], and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,18)".And we see that [tex]t_{\alpha/2}=2.10[/tex]

Now we have everything in order to replace into formula (1):

[tex]4.97-2.10\frac{0.0461}{\sqrt{19}}=4.95[/tex]    

[tex]4.97+2.10\frac{0.0461}{\sqrt{19}}=4.99[/tex]    

So on this case the 95% confidence interval would be given by (4.95;4.99)