Write a single 16-bit LC-3 instruction (in binary) that clears all the bits of R6 except the least significant two bits. In other words, after your instruction executes, bits 0 and 1 of R6 will be unchanged, and the rest of R6 will be zero.

Respuesta :

Answer:

AND R6, R6, 0003.

Explanation:

Let's say we're taking the 0003 in decimal Hexa form.  

Which is to say, 0003 = 0000 0000 0000 0011.  

The AND operation can be performed between 0003 Hex number and R6, giving the last 2 bit the same as in R6 and leaving all bits as ' 0 ' in R6.  

Answer is: AND R6, R6, 0003.

In this exercise we have to use the knowledge of binary numbers to describe the hex decimal value, so we have:

AND R6, R6, 0003.

What are binary numbers?

Binary numbers are a system based on two digits, 0 and 1, which form the language of international computing. Binary numbers form a mathematical system used by computers to create information. This system consists of a base of only two digits: 0 and 1.

So write in the hexal form:

[tex]0003 = 0000 0000 0000 0011[/tex]  

The 0003 Hex number and R6, giving the last 2 bit the same as in R6 and leaving all bits as ' 0 ' in R6.  

See more about binary at brainly.com/question/7960132