A line is perpendicular to y = 4x – 2
and intersects the point (4, -11).
What is the equation of this
perpendicular line?
y = - 3x + [?]
Hint: Use the Point-Slope Form: y - y1 = m(x - X1)
Then write the equation in slope-intercept form.

Respuesta :

Answer:

[tex]y=-\frac{1}{4}x-10[/tex]

Step-by-step explanation:

If a line is perpendicular to a line that has slope m, then the slope of the line is -1 / m.

in this case, [tex]y=4x-2[/tex]

∴ [tex]m=4[/tex] by comparing with [tex]y=mx+c[/tex]

the slope of the perpendicular line is

[tex]m=-\frac{1}{4}[/tex]

use the point-slope form: [tex]y-y_{0}=m(x-x_{0} )[/tex]

the equation of the perpendicular line is

[tex]y+11=-\frac{1}{4}(x-4)=-\frac{1}{4}x+1\\y=-\frac{1}{4}x+1-11=-\frac{1}{4}x-10[/tex]