Answer:
73.33% probability that they also took the SAT
Step-by-step explanation:
We have these following two events.
Event A: Taking the ACT exam. So P(A) = 0.3.
Event B: Taking the SAT exam. So P(B) = 0.37.
The conditional probability formula is:
[tex]P(B|A) = \frac{P(A \cap B)}{P(B)}[/tex]
In which P(B|A) is the probability of event B happening given that A has happened, [tex]P(A \cap B)[/tex] is the probability of both events hapenning.
22% of graduating seniors too both exams.
This means that [tex]P(A \cap B) = 0.22[/tex]
If the student took the ACT, what is the probability that they also took the SAT?
[tex]P(B|A) = \frac{P(A \cap B)}{P(B)} = \frac{0.22}{0.3} = 0.7333[/tex]
73.33% probability that they also took the SAT
