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In batting practice a batter hits a ball that is sitting at rest on top of a post. The ball leaves the post with a horizontal speed of 30.0 m/s. How much work did the force applied by the bat do on the ball

Respuesta :

Answer:

65.3

Explanation:

W = (1/2)mv^2

W = (1/2)(0.145kg)(30m/s)^2

Eduard22sly

The work done by the force applied by bat the bat on the ball of mass 0.145 kg is 65.25 J

Data obtained from the question

  • Mass (m) = 0.145 Kg
  • Velocity (v) = 30 m/s
  • Workdone =?

How to determine the workdone

The workdone in this case is equivalent to the kinetic energy of the ball i.e

Workdone = kinetic energy

Thus, the kinetic energy (KE) of the ball can be obtained as follow:

KE = ½mv²

KE = ½ × 0.145 × 30²

KE = ½ × 0.145 × 900

KE = 65.25 J

Thus,

Workdone = kinetic energy

Workdone = 65.25 J

Complete question

A baseball has a mass of 0.145 kg. (a) In batting practice a batter hits a ball that is sitting at rest on top of a post. The ball leaves the post with a horizontal speed of 30 m/s. How much work did the force applied by the bat do on the ball?

Learn more about energy:

https://brainly.com/question/10703928

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