Assume that x is a random variable in a probability distribution with mean μ and standard deviation σ. Find expressions for the mean and standard deviation if every value of x is modified by first being multiplied by 4, then increased by 5.

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Answer:

Find the mean, μ, for the binomial distribution which has the stated values of n and p. Round answer to the nearest tenth.

n = 676; p = 0.7

Use the given values of n and p to find the minimum usual value μ - 2σ and the maximum usual value μ + 2σ. Round your answer to the nearest hundredth unless otherwise noted.

Using statistical concepts, it is found that:

  • The mean is [tex]M = 4\mu + 5[/tex].
  • The standard deviation is [tex]S = 4\sigma[/tex]

When a constant is added to each data in a variable:  

  • The mean is incremented by this constant.
  • The standard deviation remains constant.

When a constant is multiplied to each data in a variable:

  • Both the mean and the standard deviation are multiplied by the constant.

Multiplied by 4, increased by 5, hence, applying the bullet points above:

  • The mean is [tex]M = 4\mu + 5[/tex].
  • The standard deviation is [tex]S = 4\sigma[/tex]

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