Answer:
0.325M
Explanation:
The following data were obtained from the question:
C1 =?
V1 = 28mL
C2 = 0.182M
V2 = 50mL
The molarity of the stock solution can be achieved by using the following equation:
C1V1 = C2V2
C1 x 28 = 0.182 x 50
Divide both side by 28
C1 = (0.182 x 50) /28
C1 = 0.325M
Therefore, the molarity of the stock solution is 0.325M
