Answer: f(x) = (x-4)^2+8 for vertex form.
Step-by-step explanation:
Given Quadratic Function f(x) = x^2-8x+24
As you know, the standard form is y = ax^2+bx+c where a,b and c are part of real numbers. and a musn't be 0
For vertex form, a(x-h)^2+k and (h,k) is vertex of graph.
We are going to change the standard form to vertex form so we can graph it easily.
[tex]f(x)=x^2-8x+24[/tex]
[tex]f(x)=(x^2-8x+16)-16+24[/tex] By completing the square.
[tex]f(x)=(x-4)^2+8[/tex]
Now we know vertex and that is (4,8)
For Axis of Symmetry = h
Then draw the graph.
From the graph, vertex is not on x-axis, meaning that there are no common points (The equation has a complex solution/answer.)
