Respuesta :
Answer:
0.053 L is the volume of concentrated solution that was used
Explanation:
Let's determine the answer of this, by rules of three.
There is also a dilution formula.
Molarity is a sort of concentration that indicates the moles of solute in 1L of solution.
In 1 L of concentrated solution, there are 1.5 moles of NaCl
In 1 L of diluted solution, there are 0.80 moles.
The volume for the diluted solution is 0.10L
The rule of three will be:
1L of solution has 0.80 moles of solute
Then, 0.10L of solution must have (0.1 . 0.8)/1 = 0.08 moles
This moles came from the concentrated solution, and we know that in 1L of this solution we have 1.5 moles. Therefore the rule of three will be:
1.5 moles are in 1L of solution
0.08 moles were in (0.08 . 1L / 1.5) = 0.053 L (This is the volume of concentrated solution that was used)
Dilution formula is: M conc . Vol conc = M diluted . Vol diluted
1.5 M . Vol conc = 0.80 M . 0.10L
Vol conc = 0.80 M . 0.10L / 1.5M = 0.053L
Answer:
0.053 L of stock solution was used.
Explanation:
Step 1: Data given
Concentration of the stock solution = 1.5 M NaCl
Concentration of the diluted solution = 0.80 M
Volume of the diluted solution = 0.10 L
Step 2: Calculate the volume of the stock solution
C1*V1 = C2*V2
⇒with C1 = the concentration of the stock solution = 1.5 M NaCl
⇒with V1 = the volume of the stock solution = TO DETERMINED
⇒with C2 = the concentration of the diluted solution = 0.80 M
⇒with V2 = the volume of the diluted solution = 0.10 L
1.5 M * V1 = 0.80 M * 0.10 L
V1 = (0.80 *0.10 L)/ 1.5 M
V1 = 0.053 L
0.053 L of stock solution was used.
