A restaurant offers 4 appetizers, 8 salads, 9 entrees and 7 desserts. In how many ways can a customer select a meal, if a meal consists of an appetizer, a salad, an entree and a dessert

Respuesta :

Answer: 2016 ways

Step-by-step explanation:

This is a question on selection with deals with combination

Number of ways to select one appetizer from 4 appetizer Options = 4C1

Number of ways to select one Salad from 8 salad options = 8C1

Number of ways to select one entree from 9 entrees = 9C1

Number of ways to select one dessert from 7 deserts = 7C1

Total number of ways to select the meal = 4C1 * 8C1 * 9C1 * 7C1 = 2016 ways.

The total number of ways is 2016.

Permutation:

A permutation is a collection or a combination of objects from a set where the order or the arrangement of the chosen objects does not matter.

Given that,

The choices of an appetizer=4

The choices of a salads=5

The choices of an entrees=9

The choices of a desseters=7

So, the total number of the choices is,

[tex]4\times 8\times9 \times 7=2016[/tex]

Learn more about the topic Permutation:

https://brainly.com/question/14471979