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A piston-cylinder device initially contains 0.3 kg of nitrogen gas at 160 kPa and 140oC. The nitrogen is now expanded isothermally to a pressure of 100 kPa. Determine the boundary work done during this process.

Respuesta :

Answer:

Work done by the gas is given as

[tex]W = 1.72 \times 10^4 J[/tex]

Explanation:

As we know that the process is isothermal so here work done is given as

[tex]W = nRTln(\frac{P_1}{P_2})[/tex]

here we know that

[tex]n = \frac{w}{M}[/tex]

[tex]n = \frac{300}{28} = 10.7 moles[/tex]

now we have

[tex]W = 10.7 (8.31)(273 + 140) ln(\frac{160}{100})[/tex]

so we have

[tex]W = 1.72 \times 10^4 J[/tex]

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