Answer:
4 moles of Li₃N will be produced in this reaction
Explanation:
The reaction is:
6Li + N₂ → 2Li₃N
If the nitrogen gas is the excess reactant, the limiting must be the lithium.
You always have to make calculations with the limiting reactant. You never use the excess reagent.
Ratio is 6:2.
The rule of three to solve this is:
6 moles of lithium can produce 2 moles of nitride
Therefore, 12 moles of Li must produce (12 . 2) / 6 = 4 moles of nitride
Answer:
4.0 moles of lithium nitride will be produced
Explanation:
Step 1: Data given
Number of moles lithium (Li) = 12.0 moles
Nitrogen gas (N2) is in excess.
Step 2: The balanced equation
6Li + N2 → 2Li3N
Step 3: Calculate moles of lithium nitride (Li3N)
For 6 moles Lithium we need 1 mol nitrogen gas to produce 2 moles lithium nitride
For 12.0 moles lithium we'll have 12.0/ 6 = 2.0 moles nitrogen gas to react to produce 12.0 / 3 = 4.0 moles lithium nitride
4.0 moles of lithium nitride will be produced
