Answer:
Explanation:
The equation for continuosly compounded interest is:
Where:
1. For the amount to double:
Substitute the values and solve for t:
[tex]2\times \$1,300=\$1,300\times e^{0.074t}\\ \\ 0.074t=\ln 2\\ \\ t=\ln 2/0.074=9.37years[/tex]
2. For the amount to triple:
[tex]3\times \$1,300=\$1,300\times e^{0.074t}\\ \\ 0.074t=\ln 3\\ \\ t=\ln 3/0.074=14.85years[/tex]