Explanation:
The time period of spring T = 2π[tex]\sqrt{\frac{m}{k} }[/tex]
here m is the mass with the spring
K is the spring constant
Thus T = 2π[tex]\sqrt{\frac{1.25}{250} }[/tex] = [tex]\frac{\pi \sqrt{2} }{10}[/tex] = 0.43 sec
The frequency = [tex]\frac{1}{T}[/tex] = [tex]\frac{1}{0.43}[/tex] = 2.3 Hz
