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A chair of weight 100 N lies atop a horizontal floor; the floor is not frictionless. You push on the chair with a force of F = 42.0 NN directed at an angle of 34.0∘ below the horizontal and the chair slides along the floor.Using Newton's laws, calculate , the magnitude of the normal force that the floor exerts on the chair.

Respuesta :

Answer:

The magnitude of the normal force 123.48 N.

Explanation:

Given that,

Weight of the chair, W = 100 N

Force acting on the chair, F = 42 N directed at an angle of 34.0∘ below the horizontal. We need to find the magnitude of the normal force that the floor exerts on the chair.

The net forces in vertical or y direction is given by :

[tex]N-mg-F\sin\theta=0\\\\N=mg+F\sin\theta\\\\N=100+42\times \sin(34)\\\\N=123.48\ N[/tex]

So, the magnitude of the normal force 123.48 N.

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