Answer:
Work done is 0 J.
Explanation:
Given:
Volume of the tank (V) = 1.2 m³
Initial pressure of nitrogen (P₁) = 200 kPa
Initial temperature of nitrogen (T₁) = 350 K
Final pressure of nitrogen (P₂) = 900 kPa
The volume of nitrogen gas is same as volume of tank. Now, as the tank is rigid, the volume of nitrogen gas remains the same.
We know that,
Work done on a gas is given as:
[tex]Work=P\Delta V[/tex]
Where, ΔV is the change in volume.
But, the volume here is constant. So, ΔV = 0.
Hence, the work done is also zero.
