Answer:
2.0366 m/s
Explanation:
Terminal velocity can be calculated form newton law of viscosity
Dc ( diameter of cylinder ) = 100 mm = 0.1 m
L = 0.25 m
Dh ( diameter of hollow tube ) = 102 mm = 0.102 m
μ ( viscosity ) = 2.5 Ns/m2
h ( the difference between the diameters / 2 ) = Dh - Dc / 2
= ( 0.102 - 0.1 ) / 2 = 0.002 m
The drag force of the cylinder is equal to the weight of the cylinder = 20 N expressed as
W = μ [tex]\frac{V}{h}[/tex] * A
20 = ( 2.5 ) * [tex]\frac{V}{0.002}[/tex] * ( π * d * L )
20 = (2.5 ) * [tex]\frac{V}{0.002}[/tex] * ( π * 0.1 * 0.25 )
therefore V = (20 / 0.1964) * 0.02
V = 2.0366 m/s
