Answer:
Therefore,
The volume of the geode, rounded to the nearest tenth is 640.1 feet³.
Step-by-step explanation:
Given:
Geode shaped approximately like a cylinder. such that
Height = h = 26 feet
Diameter = d = 5.6 feet
[tex]Radius = r =\dfrac{d}{2}=\dfrac{5.6}{2}=2.8\ feet[/tex]
To Find:
volume of the geode = ?
Solution:
Geode shaped approximately like a cylinder,
So, Volume of Cylinder is given by,
[tex]\textrm{Volume of Cylinder}=\pi r^{2}h[/tex]
Where,
Height = h
Radius = r
pi = 3.14
Substituting the values we get
[tex]\textrm{Volume of Cylinder}=3.14\times 2.8^{2}\times 26=640.05\approx 640.1\ feet^{3}[/tex]
Therefore,
The volume of the geode, rounded to the nearest tenth is 640.1 feet³.
