Answer : The concentration of C₄H₆ after 180 min is, 0.0052 M
Explanation :
The integrated rate law equation for second order reaction follows:
[tex]k=\frac{1}{t}\left (\frac{1}{[A]}-\frac{1}{[A]_o}\right)[/tex]
where,
k = rate constant = [tex]0.84L/(mol.min)[/tex]
t = time taken = 180 min
[A] = concentration of substance after time 't' = ?
[tex][A]_o[/tex] = Initial concentration = 0.025 M
Now put all the given values in above equation, we get:
[tex]0.84=\frac{1}{180}\left (\frac{1}{[A]}-\frac{1}{(0.025)}\right)[/tex]
[tex][A]=0.0052M[/tex]
Hence, the concentration of C₄H₆ after 180 min is, 0.0052 M
