Respuesta :
Answer:
a) [tex] P(Z> 0.07) = 1-P(Z<0.07)[/tex]
And we can use the following excel code:
"=1-NORM.DIST(0.07,0,1,TRUE)"
And we got:
[tex] P(Z>0.07) = 0.472[/tex]
b) [tex] P(Z> 0.07) = 1-P(Z<0.07)[/tex]
And we can use the following excel code:
"=1-NORM.DIST(0.07,0,1,TRUE)"
And we got:
[tex] P(Z>0.07) = 0.472[/tex]
c) [tex] P(Z> -0.92) = 1-P(Z<-0.92)[/tex]
And we can use the following excel code:
"=1-NORM.DIST(-0.92,0,1,TRUE)"
And we got:
[tex] P(Z>-0.92) = 0.821[/tex]
d) [tex] P(Z> 0.39) = 1-P(Z<0.39)[/tex]
And we can use the following excel code:
"=1-NORM.DIST(0.39,0,1,TRUE)"
And we got:
[tex] P(Z>0.39) = 0.348[/tex]
Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Solution to the problem
Part a
We want this probability:
[tex] P(Z> -0.77) [/tex]
And using the complement rule and we got:
[tex] P(Z> -0.77) = 1-P(Z<-0.77)[/tex]
And we can use the following excel code:
"=1-NORM.DIST(-0.77,0,1,TRUE)"
And we got:
[tex] P(Z>-0.77) = 0.779[/tex]
Part b
We want this probability:
[tex] P(Z> 0.07) [/tex]
And using the complement rule and we got:
[tex] P(Z> 0.07) = 1-P(Z<0.07)[/tex]
And we can use the following excel code:
"=1-NORM.DIST(0.07,0,1,TRUE)"
And we got:
[tex] P(Z>0.07) = 0.472[/tex]
Part c
We want this probability:
[tex] P(Z> -0.92) [/tex]
And using the complement rule and we got:
[tex] P(Z> -0.92) = 1-P(Z<-0.92)[/tex]
And we can use the following excel code:
"=1-NORM.DIST(-0.92,0,1,TRUE)"
And we got:
[tex] P(Z>-0.92) = 0.821[/tex]
Part d
We want this probability:
[tex] P(Z> 0.39) [/tex]
And using the complement rule and we got:
[tex] P(Z> 0.39) = 1-P(Z<0.39)[/tex]
And we can use the following excel code:
"=1-NORM.DIST(0.39,0,1,TRUE)"
And we got:
[tex] P(Z>0.39) = 0.348[/tex]