It is given that for different time span car have different speed and also the person spend [tex]40\ min=\dfrac{40}{60}\ hrs =0.67\ hrs\ .[/tex] in eating lunch and buying gas.
We know , average speed is total distance covered by total time taken .
Therefore , average speed , [tex]v=\dfrac{total\ distance }{total\ times}[/tex]
[tex]v=\dfrac{\dfrac{10}{60}\times 50+\dfrac{19}{60}\times 100+\dfrac{60}{60}\times 55}{\dfrac{10}{60}+\dfrac{10}{60}+\dfrac{60}{60}+ \dfrac{40}{60}}\\\\\\v=47.5\ m/s[/tex]
Hence, this is the required solution.
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Average speed
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