Answer:
2.58 kPa
Step-by-step explanation:
Initial Pressure of the nitrogen gas = 6.85 kPa
Initial temperature of the nitrogen gas 539 K
Final Pressure of the nitrogen gas = ???
Final Pressure of the nitrogen gas = -62°C = (273+(-62))K
= 211 K
∴ The equation that can be used to approach this question relating to pressure and temperature at a fixed constant volume is Gay-Lussac's Law of Combine Volume. The expression for Gay-Lussac's Law is given as:
[tex]\frac{P_1}{T_1} = \frac{P_2}{T_2}[/tex]
[tex]\frac{6.58kPa}{539K} =\frac{P_2}{211K}[/tex]
[tex]P_2 = \frac{(6.58kPa*211K)}{539K}[/tex]
[tex]P_2= 2.58 kPa[/tex]
Thus, the pressure will be 2.58 kPa at -62°C
