Answer:
H₂SO₄ (aq) + H₂O (l) → HSO₄⁻ (aq) + H₃O⁺ (aq)
HSO₄⁻ (aq) + H₂O (l) ⇄ SO₄⁻²(aq) + H₃O⁺ (aq) Ka
Explanation:
The sulfuric acid is a dyprotic acid.
It is a considered a strong acid but only the first deprotonation is strong.
Second deprotonation is totally weak
That's why we have equilibrium when it release the second proton.
Since a deprotonation is treated for a weak acid, the acid is considered not to completely dissociate, that's why the equilibrium
H2SO4 + H2O--------------> H3O + HSO4−
HSO4 + H2O----------------> H3O + SO4−
Sulfuric acid is a very strong acid when it is dissolve in water or in aqueous solutions it ionizes completely forming hydronium ions (H3O+) and hydrogen sulfate ions (HSO4−).
If the it is placed in dilute solutions the hydrogen sulfate ions again dissociate forming more hydronium ions and sulfate ions (SO4−) so we can conclude that sulfuric acid reacts with water forming hydronium ions (H3O+) and hydrogen sulfate ions (HSO4−).
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