Answer:
61.7 dB
Explanation:
The sound intensity of Rifle can be calculated using this formula
I ( sound intensity ) = 10 * log ( I / IO) equation 1
where I = power/area
I = 64.7 dB
hence equation 1 becomes
64.7 = 10* log ( I / IO ) equation 2
note the sound intensity was produced by 2 identical rifle hence equation 2 will become
64.7 = 10 * log ( 2P / PO ) equation 3
for a single rifle (X) equation 3 becomes
= 64.7 - 10* log (2) = 64.7 - 10*0.30 = 64.7 - 3
= 61.7 dB
t
If only one rifle were shot, the sound intensity level will be "61.7 dB".
According to the question,
When two identical rifles are shot,
Sound intensity level (I) = 64.7 dB
We know the relation,
I = [tex]\frac{Power}{Area}[/tex]
= 64.7 dB
Now,
→ I = 10 × log([tex]\frac{I}{IO}[/tex]) ...(equation 1)
By substituting the values, we get
64.7 = 10 × log([tex]\frac{I}{IO}[/tex]) ...(equation 2)
then,
Two identical rifle then,
64.7 = 10 × log([tex]\frac{2P}{PO}[/tex]) ...(equation 3)
hence,
The sound intensity level be:
= 64.7 - 10 × log(2)
= 64.7 - 10 × 0.30
= 64.7 - 3
= 61.7 dB
Thus the response above is right.
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https://brainly.com/question/17062836
