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An aluminum rod with a gauge length of 1.18 m undergoes thermal expansion from 20 oC to 92 oC. The thermal expansion coefficient and elastic modulus of aluminum are 22.2 × 10−6 K −1 and 68.9 GPa respectively

Respuesta :

Answer:

New length l2 is 1.18189

Explanation: from

L2=l1(1+alpha*change in temperature)

L2=1.18(1+(22.2*10^-6)*(92-20))

L2 =1.18189m

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