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You catch a volleyball (mass 0.270 kg) that is moving downward at 7.50 m/s. In stopping the ball, your hands and the volleyball descend together a distance of 0.150 m. How much work do your hands do on the volleyball in the process of stopping it?

Respuesta :

Answer:

Explanation:

deceleration a

v² = u² - 2as

0 = 7.5² - 2 a x .15

a = 187.5 m / s²

If R be the force exerted by hand

R- mg = ma

R = mg + ma

= .27 ( 9.8 + 187.5 )

= 53.27 N

Work done by hand

= force x displacement

= 53.27 x - .15

= -  8 J  

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